①bc(3.14159/180×0.46875)×ac(sin0.46875)×2=sin0.9375→
②ac(sin0.9375)×ab(√1-sin0.9375²)×2=sin1.875
③ac(sin1.875)×ab(√1-sin1.875²)×2=sin3.75
④ac(sin3.75)×ab(√1-sin3.75²)×2=sin7.5
⑤ac(sin3.75)×ab(√1-sin3.75²)×2=
⑥ac(sin7.5)×ab(√1-sin7.5²)×2=sin15
⑦ac(sin15)×ab(√1-sin15²)×2=sin30
ab(π/180×A/2ⁿ)×bc(cosA)×2=sinA→.....→ac×bc×2=sinA/2⁶→ac×bc×2=sinA/2⁵→ac×bc×2=sinA/2⁴→ac×bc×2=sinA/2³→ac×bc×2=sinA/2²→ac×bc)×2=sinA/2→ac×bc×2=sinA
ab(π/180×A(45)/2⁷)×ac(cos0.17578125)×2=ac(sin0.3515625)→ac(sin0.3515625)×bc√(1-sin0.3515625²)×2=sinA/2⁶(sin0.703125)→ac(sin0.703125)×bc√(1-sin0.703125²)×2=sinA/2⁵(sin1.40625)→ac(sin1.40625)×bc√(1-sin1.40625²)×2=sinA/2⁴(sin2.8125)→ac(sin2.8125)×bc√(1-sin2.8125²)×2=sinA/2³(sin5.625)→ac(sin5.625)×bc√(1-sin5.625²)×2=sinA/2²(sin11.25)→ac(sin11.25)×bc√(1-sin11.25²)×2=sinA/2(sin22.5)→ac(sin22.5)×bc√(1-sin22.5²)×2=sinA(sin45)
*sinA×cosA×2
sin30×cos30×2=sin60→sin60×cos60×2=sinA120(sin60)→sin120×cos120×2=sinA240(±sin60)→
sin240×cos240×2=sinA480(±sin60)
sin45×cos45×2=sin90(1)→sin90×cos90×2=sinA180(0)→sin180×cos180×2=sinA360(0)→
sin40×cos40×2=sin80→sin80×cos80×2=sinA160(sin60)→sin120×cos120×2=sinA240(±sin60)→
*Obtaining the abc right triangle angle.
(right triangle) →abd(Isosceles triangle)
cd=ab-cd→1-√0.75
bd=√(bc²+cd²)→√(0.5²+(1-√0.75²))=0.51763809020504
be=ed=bd½=0.2588190451025
sin15=0.2588190451025
ae=√(ab²-de²)→√(1-0.2588190451025²)=0.9659258262890
cos15=0.9659258262890
















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